If $A, B$ and $C$ are any three sets, then $A -(B \cup C)$ is equal to
$(A -B) \cup (A -C)$
$(A -B) \cap (A -C)$
$(A -B) \cup C$
$(A -B) \cap C$
If ${N_a} = [an:n \in N\} ,$ then ${N_5} \cap {N_7} = $
Show that $A \cap B=A \cap C$ need not imply $B = C$
Let $A$ and $B$ be subsets of a set $X$. Then
If $A =$ [$x:x$ is a multiple of $3$] and $B =$ [$x:x$ is a multiple of $5$], then $A -B$ is ($\bar A$ means complement of $A$)
If $A, B, C$ are three sets, then $A \cap (B \cup C)$ is equal to