If vec{A} and vec{B} are two vectors satisfyi | vedclass

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Question

$\vec{A} \vec{B}=|\vec{A} 	imes \vec{B}|$

$A B \cos 	heta=A B \sin 	heta \Rightarrow 	heta=45^{\circ}$

$|\vec{A}-\vec{B}|=\sqrt{A^{2}+B^{2}-

Vedclass · Accepted Answer

$\sqrt{A^{2}+B^{2}-\sqrt{2} A B}$

Vedclass · Answer

$\vec{A} \vec{B}=|\vec{A} 	imes \vec{B}|$

$A B \cos 	heta=A B \sin 	heta \Rightarrow 	heta=45^{\circ}$

$|\vec{A}-\vec{B}|=\sqrt{A^{2}+B^{2}-2 A B \cos 45^{\circ}}$

$=\sqrt{A^{2}+B^{2}-\sqrt{2} A B}$

If $\vec{A}$ and $\vec{B}$ are two vectors satisfying the relation $\vec{A} . \vec{B}=[\vec{A} \times \vec{B}]$. Then the value of $[\vec{A}-\vec{B}]$. will be :

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