For any two vectors overrightarrow A and ove | vedclass

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(d) $AB\cos 	heta = AB\sin 	heta $==>$	an 	heta = 1$? $	heta = 45^\circ $

$	herefore |\bar C|\, = \sqrt {{A^2} + {B^2} + 2AB\cos 45^\circ

Vedclass · Accepted Answer

$\sqrt {{A^2} + {B^2} + \sqrt 2 	imes AB} $

Vedclass · Answer

(d) $AB\cos 	heta = AB\sin 	heta $==>$	an 	heta = 1$? $	heta = 45^\circ $

$	herefore |\bar C|\, = \sqrt {{A^2} + {B^2} + 2AB\cos 45^\circ } $$ = \sqrt {{A^2} + {B^2} + \sqrt 2 AB} $

For any two vectors $\overrightarrow A $ and $\overrightarrow B $, if $\overrightarrow A \,.\,\overrightarrow B = \,\,|\overrightarrow A \times \overrightarrow B |,$ the magnitude of $\overrightarrow C = \overrightarrow A + \overrightarrow B $ is equal to

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