જો $3 \cot \theta = 4$ હોય,તો $\frac{1 - \tan^2 \theta}{1 + \tan^2 \theta} = \dots$ શોધો.

  • A
    $\frac{7}{25}$
  • B
    $\frac{4}{3}$
  • C
    $\frac{3}{4}$
  • D
    $\frac{1}{7}$

Explore More

Similar Questions

જો $\sin ^{2} 35^{\circ} + \cos ^{2} \theta = 1$ હોય,તો $\theta = \ldots \ldots \ldots \ldots$ ($^{\circ}$ માં)

$\sin 60^{\circ} \cdot \cos 30^{\circ} + \cos 60^{\circ} \cdot \sin 30^{\circ} = ..........$

લઘુકોણ $\theta$ માટે,જો $\cos \theta = \sin \theta$ હોય,તો $2 \tan^{2} \theta + \sin^{2} \theta + 1 = \ldots$

જો $\operatorname{cosec} \theta + \cot \theta = p$ હોય,તો સાબિત કરો કે $\cos \theta = \frac{p^{2} - 1}{p^{2} + 1}$.

Difficult
View Solution

સાબિત કરો કે $\sqrt{\sec ^{2} \theta+\operatorname{cosec}^{2} \theta}=\tan \theta+\cot \theta$

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo