If 3 cot theta = 4,then frac{1 - tan^2 theta} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given $3 \cot 	heta = 4$,we have $\cot 	heta = \frac{4}{3}$.Since $	an 	heta = \frac{1}{\cot 	heta}$,we get $	an 	heta = \frac{3}{4}$.Now,s

Vedclass · Accepted Answer

$\frac{7}{25}$

Vedclass · Answer

(A) Given $3 \cot 	heta = 4$,we have $\cot 	heta = \frac{4}{3}$.Since $	an 	heta = \frac{1}{\cot 	heta}$,we get $	an 	heta = \frac{3}{4}$.Now,substitute the value of $	an 	heta$ into the expression:$\frac{1 - 	an^2 	heta}{1 + 	an^2 	heta} = \frac{1 - (\frac{3}{4})^2}{1 + (\frac{3}{4})^2}$$= \frac{1 - \frac{9}{16}}{1 + \frac{9}{16}}$$= \frac{\frac{16 - 9}{16}}{\frac{16 + 9}{16}}$$= \frac{7}{25}$.

If $3 \cot \theta = 4$,then $\frac{1 - \tan^2 \theta}{1 + \tan^2 \theta} = \dots$

Similar Questions

If $\sin x = \sin 60^{\circ} \cdot \cos 30^{\circ} - \cos 60^{\circ} \cdot \sin 30^{\circ}$,then $x = \ldots$ (in $^{\circ}$)

$\sin 48^{\circ} \sec 42^{\circ} + \cos 48^{\circ} \operatorname{cosec} 42^{\circ} = \ldots \ldots \ldots \ldots$

Prove that,
$\frac{\tan A}{1+\sec A} + \frac{\tan A}{\sec A-1} = 2 \operatorname{cosec} A$

In $\Delta ABC$,$m \angle C = 90^{\circ}$ and $\cos B = \frac{1}{2}$,then $\operatorname{cosec} A = \ldots$

If $\cos (\alpha+\beta)=0,$ then $\sin (\alpha-\beta)$ can be reduced to

Vedclass Test Series

Exam Paper Generator

Online Exam Module