If sin x = sin 60^{circ} cdot cos 30^{circ} - | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the equation: $\sin x = \sin 60^{\circ} \cdot \cos 30^{\circ} - \cos 60^{\circ} \cdot \sin 30^{\circ}$.Using the trigonometric values: $\sin

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(B) Given the equation: $\sin x = \sin 60^{\circ} \cdot \cos 30^{\circ} - \cos 60^{\circ} \cdot \sin 30^{\circ}$.Using the trigonometric values: $\sin 60^{\circ} = \frac{\sqrt{3}}{2}$,$\cos 30^{\circ} = \frac{\sqrt{3}}{2}$,$\cos 60^{\circ} = \frac{1}{2}$,and $\sin 30^{\circ} = \frac{1}{2}$.Substituting these values into the equation:$\sin x = \left( \frac{\sqrt{3}}{2} \right) \cdot \left( \frac{\sqrt{3}}{2} \right) - \left( \frac{1}{2} \right) \cdot \left( \frac{1}{2} \right)$$\sin x = \frac{3}{4} - \frac{1}{4}$$\sin x = \frac{2}{4} = \frac{1}{2}$Since $\sin 30^{\circ} = \frac{1}{2}$,we have $\sin x = \sin 30^{\circ}$.Therefore,$x = 30^{\circ}$.

If $\sin x = \sin 60^{\circ} \cdot \cos 30^{\circ} - \cos 60^{\circ} \cdot \sin 30^{\circ}$,then $x = \ldots$ (in $^{\circ}$)

Similar Questions

$\frac{\sin 60^{\circ} + \cos 30^{\circ}}{1 + \sin 30^{\circ} + \cos 60^{\circ}} = \dots$

If $\operatorname{cosec} A = \sqrt{10}$,then $\sin A = \dots$

If $a \sin \theta = 3$ and $a \cos \theta = 4$,then $a = \dots$ (where $a > 0$).

$\frac{\sec \theta-1}{\sec \theta+1} = \ldots$

$\sin (45^{\circ}+\theta)-\cos (45^{\circ}-\theta)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module