Express $0.\overline{4}$ in the form $\frac{p}{q}$, where $p$ and $q$ are integers and $q \neq 0$.

Simplify the following expression: $(\sqrt{11}-\sqrt{3})^{2}$

Simplify the following:
$\frac{\sqrt{24}}{8} + \frac{\sqrt{54}}{9}$

Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ up to three places of decimal.
$\frac{6}{\sqrt{6}}$

Insert a rational number and an irrational number between the following: $\sqrt{2}$ and $\sqrt{3}$

Convert the following rational number into decimal form and state the kind of its decimal expansion:
$\frac{29}{12}$