Rationalise the denominator in each of the following and hence evaluate by taking $\sqrt{2}=1.414, \sqrt{3}=1.732$ and $\sqrt{5}=2.236,$ upto three places of decimal.
$\frac{4}{\sqrt{3}}$
Find three different irrational numbers lying between $\sqrt{3}$ and $\sqrt{5}$.
Express $1.23 \overline{4}$ in the form $\frac{p}{q} ;$ where $p$ and $q$ are integers and $q \neq 0$
Rationalise the denominator in each of the following
$\frac{3+2 \sqrt{2}}{3-2 \sqrt{2}}$
Find the value of $b$ :
$\frac{\sqrt{2}+\sqrt{3}}{3 \sqrt{2}-2 \sqrt{3}}=2-b \sqrt{6}$