If a+b+c=0, then the value of a^{3}+b^{3}+c^{ | vedclass

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Question

We know that

$a^{3}+b^{3}+c^{3}-3 a b c=(a+b+c)\left(a^{2}+b^{2}+c^{2}-a b-b c-c a\right)$

As $a+b+c=0,$ so, $a^{3}+b^{3}+c^{3}-3 a b c=(0)\left

Vedclass · Accepted Answer

$3abc$

Vedclass · Answer

We know that

$a^{3}+b^{3}+c^{3}-3 a b c=(a+b+c)\left(a^{2}+b^{2}+c^{2}-a b-b c-c a\right)$

As $a+b+c=0,$ so, $a^{3}+b^{3}+c^{3}-3 a b c=(0)\left(a^{2}+b^{2}+c^{2}-a b-b c-c a\right)=0$

Hence, $a^{3}+b^{3}+c^{3}=3 a b c$

Therefore, $(b)$ $3 abc$ is the correct answer.

If $a+b+c=0,$ then the value of $a^{3}+b^{3}+c^{3}$ is equal to

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