If $p(x)=x^{2}-2 \sqrt{2} x+1,$ then $p(2 \sqrt{2})$ is equal to
If $p(x)=x^{2}-2 \sqrt{2} x+1,$ then $p(2 \sqrt{2})$ is equal to
- A
$0$
- B
$1$
- C
$4 \sqrt{2}$
- D
$8 \sqrt{2}+1$
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