Factorise :
$x^{2}+9 x+18$
Factorise :
$x^{2}+9 x+18$
In order to factorise $x^{2}+9 x+18,$ we have to find two numbers $p$ and $q$ such that $p+q=9$ and $p q=18.$
Clearly, $6+3=9$ and $6 \times 3=18.$
So, we write the middle term $9 x$ as $6 x +3$.
$\therefore$ $x^{2}+9 x+18=x^{2}+6 x+3 x+18$
$=x(x+6)+3(x+6)$
$=(x+6)(x+3)$
Similar Questions
Which of the following expressions is a polynomial, state the reason ? If an expression is polynomial, state whether it is a polynomial in one variable or not
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Which of the following expressions is a polynomial, state the reason ? If an expression is polynomial, state whether it is a polynomial in one variable or not
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Factorise
$x^{3}+2 x^{2}-13 x+10$
Factorise
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