If R is the radius of the earth and g the acc | vedclass

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(c) $g = \frac{{GM}}{{{R^2}}}$ and $M = \frac{4}{3}\pi {R^3} 	imes D $

$	herefore \,\,g = \frac{4}{3}\frac{{\pi {R^3} 	imes GD}}{{{R^2}}}\, \Rig

Vedclass · Accepted Answer

$3g/4\pi RG$

Vedclass · Answer

(c) $g = \frac{{GM}}{{{R^2}}}$ and $M = \frac{4}{3}\pi {R^3} 	imes D $

$	herefore \,\,g = \frac{4}{3}\frac{{\pi {R^3} 	imes GD}}{{{R^2}}}\, \Rightarrow \,D = \frac{{3g.}}{{4\pi RG}}$

If $R$ is the radius of the earth and $g$ the acceleration due to gravity on the earth's surface, the mean density of the earth is

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