If $U =\{1,2,3,4,5,6,7,8,9\}, A =\{2,4,6,8\}$ and $B =\{2,3,5,7\} .$ Verify that

$(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}$

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$U=\{1,2,3,4,5,6,7,8,9\}$

$A=\{2,4,6,8\}, B=\{2,3,5,7\}$

$(A \cup B)^{\prime}=\{2,3,4,5,6,7,8\}^{\prime}=\{1,9\}$

$A^{\prime} \cap B^{\prime}=\{1,3,5,7,9\} \cap\{1,4,6,8,9\}=\{1,9\}$

$\therefore(A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}$

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