Class 12Mathematics3 and 4 .Determinants and MatricesExpansion of determinants, Solution of equation in the form of determinants and area of triangle and Equation of Line
Easyજો $\left|\begin{array}{cc}x & 2 \\ 18 & x\end{array}\right|=\left|\begin{array}{cc}6 & 2 \\ 18 & 6\end{array}\right|,$ હોય,તો $x$ ની કિંમત શોધો.
- A$6$
- B$\pm 6$
- C$-6$
- D$0$
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Similar Questions
ધારો કે $A = \begin{bmatrix} 1 & \sin \theta & 1 \\ -\sin \theta & 1 & \sin \theta \\ -1 & -\sin \theta & 1 \end{bmatrix}$,જ્યાં $0 \leq \theta \leq 2 \pi$. તો
Difficult
View Solution$\left| \begin{array}{ccc} 5^2 & 5^3 & 5^4 \\ 5^3 & 5^4 & 5^5 \\ 5^4 & 5^5 & 5^7 \end{array} \right|$ નું મૂલ્ય શોધો.
Easy
View Solutionજો $f(x) = \left| \begin{array}{ccc} x & x+1 & x+3 \\ x+2 & x+4 & x+7 \\ x+6 & x+9 & x+13 \end{array} \right|$ હોય,તો $f(5) =$
$\left| \begin{matrix} 0 & a & -b \\ -a & 0 & c \\ b & -c & 0 \end{matrix} \right| = $
Easy
View Solution$t$ ના વાસ્તવિક મૂલ્યોની સંખ્યા શોધો જેથી સમપરિમાણીય સમીકરણોની સિસ્ટમ
$\begin{aligned}
t x+(t+1) y+(t-1) z &=0 \\
(t+1) x+t y+(t+2) z &=0 \\
(t-1) x+(t+2) y+t z &=0
\end{aligned}$
ને બિન-તુચ્છ (non-trivial) ઉકેલો મળે.
$\begin{aligned}
t x+(t+1) y+(t-1) z &=0 \\
(t+1) x+t y+(t+2) z &=0 \\
(t-1) x+(t+2) y+t z &=0
\end{aligned}$
ને બિન-તુચ્છ (non-trivial) ઉકેલો મળે.
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