colum $I$ | colum $II$ |
$(A)$ $A \cdot B =| A \times B |$ | $(p)$ $\theta=90^{\circ}$ |
$(B)$ $A \cdot B = B ^2$ | $(q)$ $\theta=0^{\circ}$ or $180^{\circ}$ |
$(C)$ $|A+B|=|A-B|$ | $(r)$ $A=B$ |
$(D)$ $|A \times B|=A B$ | $(s)$ None |
Explain the geometrical interpretation of scalar product of two vectors.
If $\left| {\vec A } \right|\, = \,2$ and $\left| {\vec B } \right|\, = \,4$ then match the relation in Column $-I$ with the angle $\theta $ between $\vec A$ and $\vec B$ in Column $-II$.
Column $-I$ | Column $-II$ |
$(a)$ $\vec A \,.\,\,\vec B \, = \,\,0$ | $(i)$ $\theta = \,{0^o}$ |
$(b)$ $\vec A \,.\,\,\vec B \, = \,\,+8$ | $(ii)$ $\theta = \,{90^o}$ |
$(c)$ $\vec A \,.\,\,\vec B \, = \,\,4$ | $(iii)$ $\theta = \,{180^o}$ |
$(d)$ $\vec A \,.\,\,\vec B \, = \,\,-8$ | $(iv)$ $\theta = \,{60^o}$ |
Which of the following is not true ? If $\overrightarrow A = 3\hat i + 4\hat j$ and $\overrightarrow B = 6\hat i + 8\hat j$ where $ A$ and $B$ are the magnitudes of $\overrightarrow A $ and $\overrightarrow B $