If $L.M.V.T.$ is true for $f(x) = x(x-1)(x-2)$ on the interval $x \in [0, 1/2]$,then find the value of $C$.

  • A
    $1 + \frac{\sqrt{3}}{6}$
  • B
    $1 - \frac{\sqrt{3}}{6}$
  • C
    $\frac{3}{16}$
  • D
    Does not exist

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