If $sin^2x + sinx \,cosx -6cos^2x = 0$ and $-\frac{\pi}{2} < x < 0$, then the value of $cos2x$, is
If $sin^2x + sinx \,cosx -6cos^2x = 0$ and $-\frac{\pi}{2} < x < 0$, then the value of $cos2x$, is
- A
$-\frac{3}{5}$
- B
$\frac{3}{5}$
- C
$-\frac{4}{5}$
- D
$\frac{4}{5}$
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