Identify the statements which are True.

  • A
    The equation of the director circle of the ellipse $5x^2 + 9y^2 = 45$ is $x^2 + y^2 = 14$.
  • B
    $P$ and $Q$ are the points with eccentric angles $\theta$ and $\theta + \alpha$ on the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$,then the area of the triangle $OPQ$ is independent of $\theta$.
  • C
    The point of intersection of any tangent to a parabola and the perpendicular to it from the focus lies on the tangent at the vertex.
  • D
    All of the above.

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At the point of intersection of the rectangular hyperbola $xy = c^2$ and the parabola $y^2 = 4ax$,tangents to the rectangular hyperbola and the parabola make an angle $\theta$ and $\phi$ respectively with the $X$-axis. Then:

If $e_1$,$e_2$,and $e_3$ are eccentricities of the conics $y = x^2 - x + 3$,$\frac{x^2}{a^2} + \frac{y^2}{3a^4} = 1$,and $a^2x^2 - 3a^4y^2 = 1$ respectively,then which of the following is correct? (where $a > 1$)

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The locus of the midpoints of the chords of the hyperbola $x^2 - y^2 = a^2$ which are tangents to the parabola $x^2 = 4by$ will be -

Columns $1, 2$ and $3$ contain conics,equations of tangents to the conics,and points of contact,respectively.
$Column 1$ $Column 2$ $Column 3$
$(I) x^2+y^2=a^2$ $(i) my=m^2x+a$ $(P) (a/m^2, 2a/m)$
$(II) x^2+a^2y^2=a^2$ $(ii) y=mx+a\sqrt{m^2+1}$ $(Q) (-ma/\sqrt{m^2+1}, a/\sqrt{m^2+1})$
$(III) y^2=4ax$ $(iii) y=mx+\sqrt{a^2m^2-1}$ $(R) (-a^2m/\sqrt{a^2m^2+1}, 1/\sqrt{a^2m^2+1})$
$(IV) x^2-a^2y^2=a^2$ $(iv) y=mx+\sqrt{a^2m^2+1}$ $(S) (-a^2m/\sqrt{a^2m^2-1}, -1/\sqrt{a^2m^2-1})$

$(1)$ The tangent to a suitable conic (Column $1$) at $(\sqrt{3}, 1/2)$ is $\sqrt{3}x+2y=4$. Which combination is correct?
$(2)$ If a tangent to a suitable conic (Column $1$) is $y=x+8$ and its point of contact is $(8, 16)$,which combination is correct?
$(3)$ For $a=\sqrt{2}$,if a tangent is drawn to a suitable conic (Column $1$) at $(-1, 1)$,which combination is correct?

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