આપેલ છે કે $\frac{d}{d x}\left(\tan ^{-1} x\right)=\frac{1}{1+x^2}$ અને $\frac{d}{d x}\left(\sin h^{-1} x\right)=\frac{1}{\sqrt{1+x^2}}$. તો $\int \frac{3 x^6-2 x^4+x^2-2}{x^2+1} d x=$

  • A
    $\frac{3}{7} x^7-\frac{2}{5} x^5+\frac{1}{3} x^3-2 x+c$
  • B
    $\frac{\frac{3}{7} x^7-\frac{2}{5} x^5+\frac{1}{3} x^3-2 x}{\frac{x^3}{3}+x}+c$
  • C
    $\frac{3}{5} x^5-\frac{5}{3} x^3+6 x-8 \tan ^{-1} x+c$
  • D
    $\frac{3}{5} x^5-\frac{5}{3} x^3+6 x-8 \sinh ^{-1} x+c$

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