For the elementary reaction $M \rightarrow N$, the rate of disappearance of $M$ increases by a factor of $8$ upon doubling the concentration of $M$. The order of the reaction with respect to $M$ is :
$4$
$3$
$2$
$1$
For a chemical reaction $A \to B$ it is found that the rate of reaction doubles, when the concentration of $A$ is increased four times. The order in $A$ for this reaction is
Write differential rate expression of following reaction and give its order of reaction :
$H _{2} O _{2}+ I ^{-} \rightarrow H _{2} O + IO ^{-}$
$H _{2} O _{2}+ IO ^{-} \rightarrow H _{2} O + I ^{-}+ O _{2}$
The order of a reaction is said to be $ 2 $ with respect to a reactant $X, $ when
The reaction, ${N_2}{O_5} \longrightarrow 2NO + \frac{1}{2}\,{O_2}$ is of first order for $N_2O_5$ with rate constant $6.2 \times 10^{-4}\, s^{-1}$. what is the value of rate of reaction when $[N_2O_5] = 1.25\, mol\, L^{-1}$
For the reaction $A + B \rightarrow$ products, it is observed that
$(i)\,\,$on doubling the initial concentration of $A$ only, the rate of reaction is also doubled and
$(ii)$ on doubling the initial concentration of both $A$ and $B,$ there is a change by a factor of $8$ in the rate of the reaction.
The rate of this reaction is given by