For a chemical reaction $A \to B$ it is found that the rate of reaction doubles, when the concentration of $A$ is increased four times. The order in $A$ for this reaction is
$2$
$1$
$0.5$
$0$
If $50\%$ of a reaction occurs in $100$ seconds and $75\%$ of the reaction occurs in $200$ seconds, the order of this reaction is
Which of the following optioms correctly represents relationship between $t_{7/8}$ and $t_{1/2}$ where $t_{7/8}$ represent time required for concentration to become $\frac{1}{8} \,th$ of original for a reaction of order $'n'$
Consider the following data for the given reaction $2 \mathrm{HI}_{(\mathrm{g})} \rightarrow \mathrm{H}_{2(\mathrm{~g})}+\mathrm{I}_{2(\mathrm{~g})}$ . The order of the reaction is................
$1$ | $2$ | $3$ | |
$\mathrm{HI}\left(\mathrm{mol} \mathrm{L}^{-1}\right)$ | $0.005$ | $0.01$ | $0.02$ |
Rate $\left(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~s}-1\right)$ | $7.5 \times 10^{-4}$ | $3.0 \times 10^{-3}$ | $1.2 \times 10^{-2}$ |
Which is correct about zero order reaction
For the reaction
$2 \mathrm{H}_{2}(\mathrm{g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$
the observed rate expression is, rate $=\mathrm{k}_{\mathrm{f}}[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right] .$ The rate expression of the reverse reaction is