For integers m and n, both greater than 1 , c | vedclass

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Question

$\left( b ight)\,\,\,\,\,\,\,\frac{8}{4} = 2,\frac{{64}}{4} = 16;$ but $4$ is not prime.

        Hence ${P \wedge Q 	o

Vedclass · Accepted Answer

$Q \wedge R 	o P$

Vedclass · Answer

$\left( b ight)\,\,\,\,\,\,\,\frac{8}{4} = 2,\frac{{64}}{4} = 16;$ but $4$ is not prime.

        Hence ${P \wedge Q 	o R}$, false

$\left( c ight)\,\,\,\,\,\,\,\frac{{{{\left( 6 ight)}^2}}}{{12}} = \frac{{36}}{{12}} = 3;$ but $12$ is not prime

         Hence ${Q 	o R}$, false

$\left( d ight)\,\,\,\,\,\,\,\frac{{{{\left( 4 ight)}^2}}}{8} = \frac{{16}}{8} = 2;\frac{4}{8}$ is not an Integer

         Hence ${Q 	o P}$, flase

For integers $m$ and $n$, both greater than $1$ , consider the following three statements
$P$ : $m$ divides $n$
$Q$ : $m$ divides $n^2$
$R$ : $m$ is prime,
then true statement is

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