For any real value of $x$,if $\frac{11 x^2+12 x+6}{x^2+4 x+2} \notin(a, b]$,then the value of $x$ for which $\frac{11 x^2+12 x+6}{x^2+4 x+2}=b-a+3$ is

  • A
    $\frac{3}{4}$
  • B
    $\frac{3}{2}$
  • C
    $2$
  • D
    $-\frac{1}{2}$

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