The sum, of the squares of all the roots of t | vedclass

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Question

$ x ^2+|2 x -3|-4=0$
$	ext { Case I: } x \geq \frac{3}{2}$
$ x ^2+2 x -3-4=0$
$x^2+2 x-7=0$
$x=2 \sqrt{2}-1$
$	ext { Case II }: x<\frac{3}{2

Vedclass · Accepted Answer

$6(2-\sqrt{2})$

Vedclass · Answer

$ x ^2+|2 x -3|-4=0$
$	ext { Case I: } x \geq \frac{3}{2}$
$ x ^2+2 x -3-4=0$
$x^2+2 x-7=0$
$x=2 \sqrt{2}-1$
$	ext { Case II }: x<\frac{3}{2}$
$x^2+3-2 x-4=0$
$x^2-2 x-1=0$
$x=1-\sqrt{2}$
$	ext { Sum of squares }=(2 \sqrt{2}-1)^2+(1-\sqrt{2})^2$
$= 8-4 \sqrt{2}+1+1-2 \sqrt{2}+2$
$= 6(2-\sqrt{2}) 	herefore(3)$

The sum, of the squares of all the roots of the equation $x^2+|2 x-3|-4=0$, is :

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