કોઈપણ પૂર્ણાંક $n \geq 1$ માટે,$\sum_{K=1}^n K(K+2) =$

  • A
    $\frac{n(n+1)(n+2)}{6}$
  • B
    $\frac{n(n+1)(2n+7)}{6}$
  • C
    $\frac{n(n+1)(2n+1)}{6}$
  • D
    $\frac{n(n-1)(2n+8)}{6}$

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