For a transistor,in a common emitter arrangem | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a common emitter configuration,the alternating current gain $\beta$ (also known as the forward current gain) is defined as the ratio of the cha

Vedclass · Accepted Answer

$\beta = \left( \frac{\Delta I_C}{\Delta I_B} \right)_{V_{CE}}$

Vedclass · Answer

(A) In a common emitter configuration,the alternating current gain $\beta$ (also known as the forward current gain) is defined as the ratio of the change in collector current $\Delta I_C$ to the change in base current $\Delta I_B$,while keeping the collector-emitter voltage $V_{CE}$ constant.Mathematically,this is expressed as: $\beta = \left( \frac{\Delta I_C}{\Delta I_B} \right)_{V_{CE}}$.Since it is a ratio of two currents,$\beta$ is a dimensionless quantity. $A$ small change in the base current results in a significantly larger change in the collector current,which is the fundamental principle behind transistor amplification.

For a transistor,in a common emitter arrangement,the alternating current gain $\beta$ is given by

Similar Questions

In a transistor circuit,the emitter-base circuit of a $n-p-n$ transistor is always

The ratio $(R)$ of output resistance $r_0$ and input resistance $r_i$ in measurements of input and output characteristics of a transistor is typically in the range:

In a $NPN$ transistor,$10^8$ electrons enter the emitter in $10^{-8} \ s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

For a transistor,if the emitter current $I_E = 25 \, mA$ and the base current $I_B = 1 \, mA$,what is the ratio of the collector current $I_C$ to the emitter current $I_E$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module