In a transistor circuit,the emitter-base circuit of a $n-p-n$ transistor is always

An $npn$ transistor operates as a common emitter amplifier with a power gain of $10^{6}$. The input circuit resistance is $100\, \Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ will be (Round off to the nearest integer).

While a collector to emitter voltage is constant in a transistor,the collector current changes by $8.2 \,mA$ when the emitter current changes by $8.3 \,mA$. The value of forward current ratio is

For a common emitter amplifier,the current gain is $50$. If the emitter current is $6.6 \ mA$,then the value of the current gain when it acts as a common base amplifier is:

$A$ transistor having $\alpha=0.8$ is connected in a common-emitter configuration. When the base current changes by $6 \text{ mA}$, the change in collector current is: (in $\text{ mA}$)

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.