In a $NPN$ transistor,$10^8$ electrons enter the emitter in $10^{-8} \ s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

An unknown transistor needs to be identified as a $npn$ or $pnp$ type. $A$ multimeter,with $+ve$ and $-ve$ terminals,is used to measure resistance between different terminals of the transistor. If terminal $2$ is the base of the transistor,then which of the following is correct for a $pnp$ transistor?

According to a graph drawn between the input and output voltages of a transistor connected in common emitter configuration,the region in which the transistor acts as a switch is

The current amplification factor of a transistor in common emitter configuration is $80$. If the emitter current is $2.43 \text{ mA}$,then the base current is (in $\mu \text{A}$)

An $npn$ transistor operates as a common emitter amplifier with a power gain of $10^{6}$. The input circuit resistance is $100\, \Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ will be (Round off to the nearest integer).

In a common emitter amplifier,the input signal is applied across