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(C) The voltage gain $A_v$ of a common emitter amplifier is given by the product of current gain $\beta$ and resistance gain $\frac{R_L}{R_{in}}$.$A_v

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(C) The voltage gain $A_v$ of a common emitter amplifier is given by the product of current gain $\beta$ and resistance gain $\frac{R_L}{R_{in}}$.$A_v = \beta 	imes \frac{R_L}{R_{in}}$Given $\beta = 100$, $R_L = 10 	ext{ k}\Omega$, and $R_{in} = 1 	ext{ k}\Omega$.$A_v = 100 	imes \frac{10 	ext{ k}\Omega}{1 	ext{ k}\Omega} = 1000$.The output voltage $V_{out}$ is given by $V_{out} = A_v 	imes V_{in}$.Given $V_{in} = 1 	ext{ mV} = 10^{-3} 	ext{ V}$.$V_{out} = 1000 	imes 10^{-3} 	ext{ V} = 1 	ext{ V}$.

For a common emitter transistor amplifier, the current gain is $\beta = 100$. Given the input voltage $V_{in} = 1 \text{ mV}$, input resistance $R_{in} = 1 \text{ k}\Omega$, and load resistance $R_L = 10 \text{ k}\Omega$, calculate the output voltage $V_{out}$ in $\text{V}$.

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