In the common emitter configuration of a tran | vedclass

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(D) In a transistor,the emitter current is the sum of the base current and the collector current: $I_{e} = I_{b} + I_{c}$.Since $I_{b}$ and $I_{c}$ ar

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$I_{c} > I_{b}$

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(D) In a transistor,the emitter current is the sum of the base current and the collector current: $I_{e} = I_{b} + I_{c}$.Since $I_{b}$ and $I_{c}$ are both positive currents,it follows that $I_{c} The current gain in common emitter configuration is defined as $\beta = \frac{I_{c}}{I_{b}}$.For a transistor,$I_{c}$ is typically much larger than $I_{b}$ (since the base region is very thin and lightly doped),which makes $\beta > 1$.Therefore,the condition $I_{c} > I_{b}$ is the fundamental reason why the current gain $\beta$ is greater than $1$.

In the common emitter configuration of a transistor,the current gain is more than $1$. Given that $I_{b}$,$I_{e}$,and $I_{c}$ are the base,emitter,and collector currents respectively,which of the following relations is correct?

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