In an amplifier circuit,the value of the load | vedclass

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(A) Given: Load resistance $R_L = 2 	ext{ k}\Omega = 2 	imes 10^3 	ext{ }\Omega$.Change in base current $\Delta I_B = 10 	ext{ }\mu	ext{A} = 10^{

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$2$

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(A) Given: Load resistance $R_L = 2 	ext{ k}\Omega = 2 	imes 10^3 	ext{ }\Omega$.Change in base current $\Delta I_B = 10 	ext{ }\mu	ext{A} = 10^{-5} 	ext{ A}$.Change in collector current $\Delta I_C = 1 	ext{ mA} = 10^{-3} 	ext{ A}$.The change in collector-emitter voltage is given by the formula $\Delta V_{CE} = R_L 	imes \Delta I_C$.Substituting the values: $\Delta V_{CE} = (2 	imes 10^3 	ext{ }\Omega) 	imes (10^{-3} 	ext{ A}) = 2 	ext{ V}$.Therefore,the change in collector-emitter voltage is $2 	ext{ V}$.

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.

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