Find the zeroes of the polynomial:

p(x)=(x | vedclass

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Question

Let $p(x)=(x-2)^{2}-(x+2)^{2}$

As fining a zero of $p ( x )$, is same as solving the equation $p ( x )=0$

So, $p(x)=0 \Rightarrow(x-2)^{2}-(x+2)

Vedclass · Accepted Answer

$0$

Vedclass · Answer

Let $p(x)=(x-2)^{2}-(x+2)^{2}$

As fining a zero of $p ( x )$, is same as solving the equation $p ( x )=0$

So, $p(x)=0 \Rightarrow(x-2)^{2}-(x+2)^{2}=0$

$\Rightarrow(x-2+x+2)(x-2-x-2)=0$

$\Rightarrow 2 x(-4)=0 \Rightarrow-8 x=0 \Rightarrow x=0$

Hence, $x=0$ is the only one zero of $p(x)$

Find the zeroes of the polynomial:

$p(x)=(x-2)^{2}-(x+2)^{2}$

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