Factorise: 49x^2 - 121 | vedclass

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Question

(B) The given expression is $49x^2 - 121$.This can be written in the form of $a^2 - b^2$ as follows:$49x^2 - 121 = (7x)^2 - (11)^2$.Using the algebrai

Vedclass · Accepted Answer

$(7x + 11)(7x - 11)$

Vedclass · Answer

(B) The given expression is $49x^2 - 121$.This can be written in the form of $a^2 - b^2$ as follows:$49x^2 - 121 = (7x)^2 - (11)^2$.Using the algebraic identity $a^2 - b^2 = (a + b)(a - b)$,where $a = 7x$ and $b = 11$,we get:$(7x)^2 - (11)^2 = (7x + 11)(7x - 11)$.Therefore,the factors are $(7x + 11)(7x - 11)$.

Factorise: $49x^2 - 121$

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