(A) Let $p(x) = x^{3} - ax^{2} + 2x + a - 1$.Since $(x - a)$ is a factor of $p(x)$,by the Factor Theorem,$p(a) = 0$.Substituting $x = a$ in the polyno

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(A) Let $p(x) = x^{3} - ax^{2} + 2x + a - 1$.Since $(x - a)$ is a factor of $p(x)$,by the Factor Theorem,$p(a) = 0$.Substituting $x = a$ in the polynomial:$p(a) = (a)^{3} - a(a)^{2} + 2(a) + a - 1 = 0$.$a^{3} - a^{3} + 2a + a - 1 = 0$.$3a - 1 = 0$.$3a = 1$.Therefore,$a = 1/3$.