श्रेणी $1 \times 2 \times 3 + 2 \times 3 \times 4 + 3 \times 4 \times 5 + \ldots$ के $n$ पदों का योग ज्ञात कीजिए।
- A$\frac{n(n+1)(n+2)(n+3)}{4}$
- B$\frac{n(n+1)(n+2)(n+4)}{4}$
- C$\frac{n(n+1)(n+2)(n+5)}{4}$
- D$\frac{n(n+1)(n+3)(n+4)}{4}$
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Similar Questions
यदि श्रेणी $\frac{1}{5}+\frac{2}{65}+\frac{3}{325}+\frac{4}{1025}+\frac{5}{2501}+\ldots$ के प्रथम दस पदों का योग $\frac{m}{n}$ है,जहाँ $m$ और $n$ सह-अभाज्य संख्याएँ हैं,तो $m + n$ का मान ज्ञात कीजिए।
DifficultJEE MAIN 2022
View Solutionयदि $\frac{1}{2 \times 3 \times 4} + \frac{1}{3 \times 4 \times 5} + \frac{1}{4 \times 5 \times 6} + \dots + \frac{1}{100 \times 101 \times 102} = \frac{k}{101}$ है,तो $34k$ का मान $.....$ है।
DifficultJEE MAIN 2022
View Solutionश्रेणी $\frac{1}{\sqrt{1} + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + ... + \frac{1}{\sqrt{n^2 - 1} + \sqrt{n^2}}$ का योगफल क्या है?
Medium
View Solution$\lim _{n \rightarrow \infty} \left( \frac{1}{3 \cdot 7} + \frac{1}{7 \cdot 11} + \frac{1}{11 \cdot 15} + \ldots + n \text{ पद} \right) =$
यदि $n = 1, 2, 3, \dots$ के लिए ${t_n} = \frac{1}{4}(n + 2)(n + 3)$ है,तो $\frac{1}{t_1} + \frac{1}{t_2} + \frac{1}{t_3} + \dots + \frac{1}{t_{2003}} = $
Difficult
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