Find the median of the following frequency di | vedclass

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(D) To find the median,we first prepare the cumulative frequency table:						Class			Frequency $(f)$			Cumulative Frequency $(cf)$							$65-85$			$4$

Vedclass · Accepted Answer

$137$

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(D) To find the median,we first prepare the cumulative frequency table:						Class			Frequency $(f)$			Cumulative Frequency $(cf)$							$65-85$			$4$			$4$							$85-105$			$5$			$9$							$105-125$			$13$			$22$							$125-145$			$20$			$42$							$145-165$			$14$			$56$							$165-185$			$8$			$64$							$185-205$			$4$			$68$			Here,total frequency $n = 68$.$	herefore \frac{n}{2} = \frac{68}{2} = 34$.The cumulative frequency just greater than $34$ is $42$,which corresponds to the class interval $125-145$.Thus,the median class is $125-145$.Here,$l = 125$,$cf = 22$,$f = 20$,and class size $h = 20$.Using the median formula: $M = l + \left( \frac{\frac{n}{2} - cf}{f} ight) 	imes h$$M = 125 + \left( \frac{34 - 22}{20} ight) 	imes 20$$M = 125 + 12 = 137$.Therefore,the median of the given frequency distribution is $137$.

Class	$200-299$	$300-399$	$400-499$	$500-599$	$600-699$	$700-799$	$800-899$
Frequency	$3$	$61$	$118$	$139$	$126$	$151$	$2$

Marks	$30-35$	$35-40$	$40-45$	$45-50$	$50-55$	$55-60$	$60-65$
Frequency	$14$	$16$	$18$	$23$	$18$	$8$	$3$

Find the median of the following frequency distribution:

Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$

Frequency $4$ $5$ $13$ $20$ $14$ $8$ $4$

Similar Questions

Find the mean of the following data:

Class $200-299$ $300-399$ $400-499$ $500-599$ $600-699$ $700-799$ $800-899$

Frequency $3$ $61$ $118$ $139$ $126$ $151$ $2$

The percentage of marks obtained by $100$ students in an examination are given below:

Marks $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$

Frequency $14$ $16$ $18$ $23$ $18$ $8$ $3$

Determine the median percentage of marks.

The two types of Ogives drawn for a frequency distribution intersect at point $(20, 25)$. Then,the median of the data is .......

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$n = \ldots \ldots \ldots$

Cumulative frequency distribution is used to calculate the $\ldots \ldots \ldots$ of a frequency distribution.

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Class	$65-85$	$85-105$	$105-125$	$125-145$	$145-165$	$165-185$	$185-205$
Frequency	$4$	$5$	$13$	$20$	$14$	$8$	$4$

Find the median of the following frequency distribution: Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$ Frequency $4$ $5$ $13$ $20$ $14$ $8$ $4$