Find the mean of the following data: Cla | vedclass

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(A) To find the mean,we use the step-deviation method with assumed mean $A = 549.5$ and class size $c = 100$.						Class			Frequency $(f_{i})$			Midpo

Vedclass · Accepted Answer

$580.33$

Vedclass · Answer

(A) To find the mean,we use the step-deviation method with assumed mean $A = 549.5$ and class size $c = 100$.						Class			Frequency $(f_{i})$			Midpoint $(x_{i})$			$u_{i} = \frac{x_{i} - A}{c}$			$f_{i} u_{i}$							$200-299$			$3$			$249.5$			$-3$			$-9$							$300-399$			$61$			$349.5$			$-2$			$-122$							$400-499$			$118$			$449.5$			$-1$			$-118$							$500-599$			$139$			$549.5 (A)$			$0$			$0$							$600-699$			$126$			$649.5$			$1$			$126$							$700-799$			$151$			$749.5$			$2$			$302$							$800-899$			$2$			$849.5$			$3$			$6$							Total			$\Sigma f_{i} = 600$			-			-			$\Sigma f_{i} u_{i} = 185$			The formula for the mean is $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} ight) 	imes c$.Substituting the values:$\bar{x} = 549.5 + \left( \frac{185}{600} ight) 	imes 100$$\bar{x} = 549.5 + \frac{185}{6}$$\bar{x} = 549.5 + 30.833...$$\bar{x} \approx 580.33$Thus,the mean of the data is $580.33$.

Marks obtained	Number of students
More than or equal to $0$	$63$
More than or equal to $10$	$58$
More than or equal to $20$	$55$
More than or equal to $30$	$51$
More than or equal to $40$	$48$
More than or equal to $50$	$42$

Find the mean of the following data:

Class $200-299$ $300-399$ $400-499$ $500-599$ $600-699$ $700-799$ $800-899$

Frequency $3$ $61$ $118$ $139$ $126$ $151$ $2$

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Class	$200-299$	$300-399$	$400-499$	$500-599$	$600-699$	$700-799$	$800-899$
Frequency	$3$	$61$	$118$	$139$	$126$	$151$	$2$

Find the mean of the following data: Class $200-299$ $300-399$ $400-499$ $500-599$ $600-699$ $700-799$ $800-899$ Frequency $3$ $61$ $118$ $139$ $126$ $151$ $2$