The percentage of marks obtained by 100 stude | vedclass

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(B) 						Marks (Class)			Frequency $(f)$			Cumulative Frequency $(cf)$							$30-35$			$14$			$14$							$35-40$			$16$			$30$							$40-45$			$18$

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$45.4$

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(B) 						Marks (Class)			Frequency $(f)$			Cumulative Frequency $(cf)$							$30-35$			$14$			$14$							$35-40$			$16$			$30$							$40-45$			$18$			$48$							$45-50$			$23$			$71$							$50-55$			$18$			$89$							$55-60$			$8$			$97$							$60-65$			$3$			$100$			Here,$n = 100$.Therefore,$\frac{n}{2} = \frac{100}{2} = 50$.The cumulative frequency just greater than $50$ is $71$,which corresponds to the class interval $45-50$. Thus,the median class is $45-50$.$l$ (lower limit of median class) $= 45$$cf$ (cumulative frequency of class preceding median class) $= 48$$f$ (frequency of median class) $= 23$$h$ (class size) $= 5$Median formula: $	ext{Median} = l + \left( \frac{\frac{n}{2} - cf}{f} ight) 	imes h$$	ext{Median} = 45 + \left( \frac{50 - 48}{23} ight) 	imes 5$$	ext{Median} = 45 + \left( \frac{2}{23} ight) 	imes 5$$	ext{Median} = 45 + \frac{10}{23} \approx 45 + 0.4347 \approx 45.43$Rounding to one decimal place,the median percentage of marks is $45.4$.

Speed $(km/h)$	$85-100$	$100-115$	$115-130$	$130-145$
Number of players	$11$	$9$	$8$	$5$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$4$	$10$	$20$	$18$	$20$	$16$	$10$

The percentage of marks obtained by $100$ students in an examination are given below:

Marks $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$

Frequency $14$ $16$ $18$ $23$ $18$ $8$ $3$

Determine the median percentage of marks.

Similar Questions

The maximum bowling speeds,in $km/h$,of $33$ players at a cricket coaching centre are given as follows:

Speed $(km/h)$ $85-100$ $100-115$ $115-130$ $130-145$

Number of players $11$ $9$ $8$ $5$

Calculate the median bowling speed (in $km/h$).

For a given frequency distribution,$A=49.5, \Sigma f_{i}=40, \Sigma f_{i} u_{i}=-5$ and $c=20$. Then,mean $\bar{x}=$ ............

$\Sigma(x_{i} - \bar{x}) = \ldots \ldots \ldots$

Find the mean of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $2$ $4$ $10$ $20$ $18$ $20$ $16$ $10$

In the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$\Sigma f_{i}$ represents ........

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Marks	$30-35$	$35-40$	$40-45$	$45-50$	$50-55$	$55-60$	$60-65$
Frequency	$14$	$16$	$18$	$23$	$18$	$8$	$3$

The percentage of marks obtained by $100$ students in an examination are given below: Marks $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ Frequency $14$ $16$ $18$ $23$ $18$ $8$ $3$ Determine the median percentage of marks.