Find the derivative of the function f(x) = (x | vedclass

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(A) Let $f(x) = (x-1)(x-2) = x^2 - 3x + 2$. By the first principle of derivatives,$f'(x) = \lim_{h 	o 0} \frac{f(x+h) - f(x)}{h}$. Substituting $f(x+

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$2x - 3$

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(A) Let $f(x) = (x-1)(x-2) = x^2 - 3x + 2$. By the first principle of derivatives,$f'(x) = \lim_{h 	o 0} \frac{f(x+h) - f(x)}{h}$. Substituting $f(x+h) = (x+h)^2 - 3(x+h) + 2$: $f'(x) = \lim_{h 	o 0} \frac{[(x+h)^2 - 3(x+h) + 2] - [x^2 - 3x + 2]}{h}$ $f'(x) = \lim_{h 	o 0} \frac{x^2 + 2xh + h^2 - 3x - 3h + 2 - x^2 + 3x - 2}{h}$ $f'(x) = \lim_{h 	o 0} \frac{2xh + h^2 - 3h}{h}$ $f'(x) = \lim_{h 	o 0} (2x + h - 3)$ As $h 	o 0$,$f'(x) = 2x - 3$.

Find the derivative of the function $f(x) = (x-1)(x-2)$ using the first principle.

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