If f(a) = 2, f'(a) = 1, g(a) = -1, g'(a) = 2, | vedclass

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(B) Let $L = \lim_{x 	o a} \frac{g(x)f(a) - g(a)f(x)}{x - a}$.Adding and subtracting $g(a)f(a)$ in the numerator:$L = \lim_{x 	o a} \frac{g(x)f(a) -

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$5$

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(B) Let $L = \lim_{x 	o a} \frac{g(x)f(a) - g(a)f(x)}{x - a}$.Adding and subtracting $g(a)f(a)$ in the numerator:$L = \lim_{x 	o a} \frac{g(x)f(a) - g(a)f(a) + g(a)f(a) - g(a)f(x)}{x - a}$$L = \lim_{x 	o a} \left[ f(a) \frac{g(x) - g(a)}{x - a} - g(a) \frac{f(x) - f(a)}{x - a} ight]$Using the definition of the derivative,$\lim_{x 	o a} \frac{g(x) - g(a)}{x - a} = g'(a)$ and $\lim_{x 	o a} \frac{f(x) - f(a)}{x - a} = f'(a)$.$L = f(a)g'(a) - g(a)f'(a)$Substituting the given values: $L = (2)(2) - (-1)(1) = 4 + 1 = 5$.

If $f(a) = 2, f'(a) = 1, g(a) = -1, g'(a) = 2$,then $\lim_{x \to a} \frac{g(x)f(a) - g(a)f(x)}{x - a} = $

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