અંશ માપ શોધો. ( $\pi=\frac{22}{7}$ લો. ) $\frac{11}{16}$
અંશ માપ શોધો. ( $\pi=\frac{22}{7}$ લો. ) $\frac{11}{16}$
We know that $\pi$ radian $=180^{\circ}$
$\therefore \frac{11}{16}$ radian $=\frac{180}{\pi} \times \frac{11}{16}$ degree $=\frac{45 \times 11}{\pi \times 4}$ degree
$=\frac{45 \times 11 \times 7}{22 \times 4}$ degree $=\frac{315}{8}$ degree
$=36 \frac{3}{8}$ degree
$=39^{\circ}+\frac{3 \times 60}{8}$ minutes $\left[1^{\circ}=60^{\prime}\right]$
$=39^{\circ}+22^{\prime}+\frac{1}{2}$ minutes
$=39^{\circ} 22^{\prime} 30^{\prime \prime} \quad\left[1^{\prime}=60^{\prime \prime}\right]$
Similar Questions
$2({\sin ^6}\theta + {\cos ^6}\theta ) - 3({\sin ^4}\theta + {\cos ^4}\theta ) + 1 =$
$2({\sin ^6}\theta + {\cos ^6}\theta ) - 3({\sin ^4}\theta + {\cos ^4}\theta ) + 1 =$
${\sin ^2}{5^o} + {\sin ^2}{10^o} + {\sin ^2}{15^o} + ... + $ ${\sin ^2}{85^o} + {\sin ^2}{90^o} = . ..$
${\sin ^2}{5^o} + {\sin ^2}{10^o} + {\sin ^2}{15^o} + ... + $ ${\sin ^2}{85^o} + {\sin ^2}{90^o} = . ..$
જો $x\sin 45^\circ {\cos ^2}60^\circ = \frac{{{{\tan }^2}60^\circ {\rm{cosec}}30^\circ }}{{\sec 45^\circ {{\cot }^2}30^\circ }},$ તો $x = $
જો $x\sin 45^\circ {\cos ^2}60^\circ = \frac{{{{\tan }^2}60^\circ {\rm{cosec}}30^\circ }}{{\sec 45^\circ {{\cot }^2}30^\circ }},$ તો $x = $
$\sin \frac{x}{2}, \cos \frac{x}{2}$ અને $\tan \frac{x}{2}$ ની કિંમતો શોધો.: $\tan x=\frac{-4}{3}, x$ એ બીજા ચરણમાં છે.
$\sin \frac{x}{2}, \cos \frac{x}{2}$ અને $\tan \frac{x}{2}$ ની કિંમતો શોધો.: $\tan x=\frac{-4}{3}, x$ એ બીજા ચરણમાં છે.
જો $\sin x=-\frac{3}{5}$, જ્યાં $\pi < x < \frac{3 \pi}{2}$, તો $80\left(\tan ^2 x-\cos x\right)=$...........
જો $\sin x=-\frac{3}{5}$, જ્યાં $\pi < x < \frac{3 \pi}{2}$, તો $80\left(\tan ^2 x-\cos x\right)=$...........
- [JEE MAIN 2024]