Find the area of the flower bed (with semi-circular ends) shown in $Fig.$

1061-38

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Length and breadth of a circular bed are $38 \,cm$ and $10 \,cm .$

$\therefore$ Area of rectangle $ACDF =$ Length $\times$ Breadth $=38 \times 10=380 \,cm ^{2}$

Both ends of flower bed are semi-circles.

$\therefore$ Radius of semi-circle $=\frac{D F}{2}=\frac{10}{2}=5\, cm$

$\therefore$ $=\frac{\pi r^{2}}{2}=\frac{\pi}{2}(5)^{2}=\frac{25 \pi}{2} \,cm ^{2}$

$\therefore$ $=2 \times \frac{25}{2} \pi=25 \pi \,cm ^{2}$

$\therefore$ Total area of flower bed $=$ Area of rectangle $A C D F+$ Area of two semi-circles

$=(380+25 \pi) \,cm ^{2}$

 

1061-s38

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