In odot( O , r), the length of minor widehat{ | vedclass

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Question

Length of minor $\widehat{ ACB }=\frac{\pi r 	heta}{180}$

$	herefore \frac{1}{6} 	imes$ circumference $=\frac{\pi r 	heta}{180}$

$	herefore

Vedclass · Accepted Answer

$60$

Vedclass · Answer

Length of minor $\widehat{ ACB }=\frac{\pi r 	heta}{180}$

$	herefore \frac{1}{6} 	imes$ circumference $=\frac{\pi r 	heta}{180}$

$	herefore \frac{1}{6} 	imes 2 \pi r=\frac{\pi r 	heta}{180}$

$	herefore \frac{1}{6} 	imes 2 \pi r 	imes \frac{180}{\pi r}=	heta$

$	herefore 	heta=60$

In $\odot( O , r),$ the length of minor $\widehat{ ACB }$ is $\frac{1}{6}$ times the circumference of the circle. Then, the measure of the angle subtended at the centre by minor $\widehat{ ACB }$ is .........

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