Class 11MathematicsSequences and Seriesnth term of special series, Sum to n terms and Infinite number of terms
EasyFind the $9^{\text{th}}$ term in the sequence whose $n^{\text{th}}$ term is given by $a_{n} = (-1)^{n-1} n^{3}$.
- A$729$
- B$-729$
- C$81$
- D$-81$
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Similar Questions
The ${n^{th}}$ term of the series $\frac{1^3}{1} + \frac{1^3 + 2^3}{1 + 3} + \frac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \dots$ is:
Difficult
View SolutionFind the sum of the following series up to $n$ terms:
$0.6 + 0.66 + 0.666 + \dots$
$0.6 + 0.66 + 0.666 + \dots$
Difficult
View SolutionFind the sum to $n$ terms of the series $3 \times 8 + 6 \times 11 + 9 \times 14 + \dots$
Medium
View Solution$\sum\limits_{n = 1}^\infty {\sum\limits_{k = 1}^{n - 1} {\frac{k}{{{2^{n + k}}}}} } $ is equal to
The sum to infinity of the following series $\frac{1}{1 \times 2} + \frac{1}{2 \times 3} + \frac{1}{3 \times 4} + \dots$ is
Easy
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