Let $T_r$ be the $r^{\text {th }}$ term of an $A.P.$ If for some $m$, $T _{ m }=\frac{1}{25}, T_{25}=\frac{1}{20}$ and $20 \sum_{ r =1}^{25} T_{ r }=13$, then $5 m \sum_{ r = m }^{2 m} T _{ r }$ is equal to:

  • [JEE MAIN 2025]
  • A
    $112$
  • B
    $126$
  • C
    $98$
  • D
    $142$

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  • [JEE MAIN 2023]