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(A) First,we calculate the mean $\bar{x}$ of the given data:$\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{(2 	imes 2) + (5 	imes 8) + (6 	imes

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$2.3$

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(A) First,we calculate the mean $\bar{x}$ of the given data:$\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{(2 	imes 2) + (5 	imes 8) + (6 	imes 10) + (8 	imes 7) + (10 	imes 8) + (12 	imes 5)}{2 + 8 + 10 + 7 + 8 + 5} = \frac{4 + 40 + 60 + 56 + 80 + 60}{40} = \frac{300}{40} = 7.5$Next,we calculate the mean deviation about the mean using the formula $M.D.(\bar{x}) = \frac{\sum f_i |x_i - \bar{x}|}{N}$:						$x_i$			$f_i$			$|x_i - 7.5|$			$f_i |x_i - 7.5|$							$2$			$2$			$5.5$			$11$							$5$			$8$			$2.5$			$20$							$6$			$10$			$1.5$			$15$							$8$			$7$			$0.5$			$3.5$							$10$			$8$			$2.5$			$20$							$12$			$5$			$4.5$			$22.5$							Total			$40$			-			$92$			$M.D.(\bar{x}) = \frac{92}{40} = 2.3$

Find the mean deviation about the mean for the following data:

${x_i}$ $2$ $5$ $6$ $8$ $10$ $12$

${f_i}$ $2$ $8$ $10$ $7$ $8$ $5$

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Find the mean deviation about the mean for the following data: ${x_i}$ $2$ $5$ $6$ $8$ $10$ $12$ ${f_i}$ $2$ $8$ $10$ $7$ $8$ $5$