Find $p(0)$,$p(1)$,and $p(-2)$ for the following polynomial:
$p(x) = 10x - 4x^{2} - 3$
$p(x) = 10x - 4x^{2} - 3$
Given the polynomial $p(x) = 10x - 4x^{2} - 3$.
$(i)$ To find $p(0)$,substitute $x = 0$ into the polynomial:
$p(0) = 10(0) - 4(0)^{2} - 3 = 0 - 0 - 3 = -3$.
$(ii)$ To find $p(1)$,substitute $x = 1$ into the polynomial:
$p(1) = 10(1) - 4(1)^{2} - 3 = 10 - 4 - 3 = 3$.
$(iii)$ To find $p(-2)$,substitute $x = -2$ into the polynomial:
$p(-2) = 10(-2) - 4(-2)^{2} - 3 = -20 - 4(4) - 3 = -20 - 16 - 3 = -39$.
$(i)$ To find $p(0)$,substitute $x = 0$ into the polynomial:
$p(0) = 10(0) - 4(0)^{2} - 3 = 0 - 0 - 3 = -3$.
$(ii)$ To find $p(1)$,substitute $x = 1$ into the polynomial:
$p(1) = 10(1) - 4(1)^{2} - 3 = 10 - 4 - 3 = 3$.
$(iii)$ To find $p(-2)$,substitute $x = -2$ into the polynomial:
$p(-2) = 10(-2) - 4(-2)^{2} - 3 = -20 - 4(4) - 3 = -20 - 16 - 3 = -39$.
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