Factorise the following:
$1-64 a^{3}-12 a+48 a^{2}$
Factorise the following:
$1-64 a^{3}-12 a+48 a^{2}$
$1-64 a^{3}-12 a+48 a^{2}=(1)^{3}-(4 a)^{3}-3(1)(4 a)(1-4 a)$
$=(1-4 a)^{3}\left[\because a^{3}-b^{3}-3 a b(a-b)=(a-b)^{3}\right]$
$=(1-4 a)(1-4 a)(1-4 a)$
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