Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(y)=y^{2}-y+1$
Find $p(0)$, $p(1)$ and $p(2)$ for of the following polynomials : $p(y)=y^{2}-y+1$
$p(y)=y^{2}-y+1$
$\because $ $p(y)=y^{2}-y+1=(y)^{2}-y+1$
$\therefore$ $p(0)=(0)^{2}-(0)+1=0-0+1=1$
$p(1)=(1)^{2}-(1)+1=1-1+1=1$
$p(2)=(2)^{2}-2+1=4-2+1=3$
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