(B) To find the decimal expansion of $\frac{2}{3}$, we perform long division by dividing $2$ by $3$.When we divide $2$ by $3$, we get $0.666...$ which

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(B) To find the decimal expansion of $\frac{2}{3}$, we perform long division by dividing $2$ by $3$.When we divide $2$ by $3$, we get $0.666...$ which can be written as $0.\overline{6}$.Since the remainder never becomes $0$ and the digit $6$ repeats infinitely, the decimal expansion is non-terminating and recurring.

Class 9 Mathematics Number Systems Mix Examples - Number Systems

Easy

Fill in the blanks to make the following statement true: The decimal expansion of $\frac{2}{3}$ is of $\ldots \ldots$ type.

A
terminating
B
non-terminating recurring
C
non-terminating non-recurring
D
none of these

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Class 9 Questions

Class 9

Mathematics Questions

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Number Systems

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Mix Examples - Number Systems

For each question,select the proper option from four options given,to make the statement true: $\sqrt{5^{2}+12^{2}}$ is a / an $\ldots \ldots$ number.

Easy

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If $x = 5 + 2\sqrt{6}$,then find the value of $x^{2} + \frac{1}{x^{2}}$ and $x^{3} + \frac{1}{x^{3}}$.

Difficult

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Find the value of $\frac{4}{(216)^{-\frac{2}{3}}} + \frac{1}{(256)^{-\frac{3}{4}}} + \frac{2}{(243)^{-\frac{1}{5}}}$.

Medium

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Prove that,$\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}=1$.

Medium

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Express $0.\overline{4}$ in the form $\frac{p}{q}$, where $p$ and $q$ are integers and $q \neq 0$.

Medium

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Fill in the blanks to make the following statement true: The decimal expansion of $\frac{2}{3}$ is of $\ldots \ldots$ type.

Similar Questions

For each question,select the proper option from four options given,to make the statement true: $\sqrt{5^{2}+12^{2}}$ is a / an $\ldots \ldots$ number.

If $x = 5 + 2\sqrt{6}$,then find the value of $x^{2} + \frac{1}{x^{2}}$ and $x^{3} + \frac{1}{x^{3}}$.

Find the value of $\frac{4}{(216)^{-\frac{2}{3}}} + \frac{1}{(256)^{-\frac{3}{4}}} + \frac{2}{(243)^{-\frac{1}{5}}}$.

Prove that,$\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}=1$.

Express $0.\overline{4}$ in the form $\frac{p}{q}$, where $p$ and $q$ are integers and $q \neq 0$.

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